64x^2-24x-64=0

Solution for 64x^2-24x-64=0 equation:

64x^2-24x-64=0

a = 64; b = -24; c = -64;
Δ = b2-4ac
Δ = -242-4·64·(-64)
Δ = 16960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16960}=\sqrt{64*265}=\sqrt{64}*\sqrt{265}=8\sqrt{265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8\sqrt{265}}{2*64}=\frac{24-8\sqrt{265}}{128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8\sqrt{265}}{2*64}=\frac{24+8\sqrt{265}}{128}
$